If it's not what You are looking for type in the equation solver your own equation and let us solve it.
24k^2+49k=0
a = 24; b = 49; c = 0;
Δ = b2-4ac
Δ = 492-4·24·0
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-49}{2*24}=\frac{-98}{48} =-2+1/24 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+49}{2*24}=\frac{0}{48} =0 $
| -0.54=0.04h | | 32=k(4)^2 | | 32=k(4)(4) | | 4.5=0.8n | | 3（p-2）=18 | | 2/3g-7=13 | | 0.5k+2.1=7.6 | | 8/9p=-32/27 | | 3(x-5)=9+7x | | 10x-2(7x+4)=x | | (5v^2+2v)+(-v^2+3v)=-10 | | 2a-6+5a=3(a+2)+12 | | 6(−2g−1)=−(13g+2)6 | | 2t-6=12-t | | 0.8=250/x | | x/4=-5+(x+14)/3 | | 4x^2-20x+28=3 | | 6a+14=4a+40 | | 1.5x+x=3275 | | 40-5x=8(x-8) | | 25=5(2x+4)-7 | | 45x-750+15x=60 | | 7t+9=3t+37 | | 8x=29-11x | | x3=64/125 | | -216=8(3-6x) | | 3/4x+7/8x=28/12 | | 16x2+2x−5=0 | | 3(5+2x)=1-x | | -3275+x=1.5 | | 3275+x=1.5 | | 7j-7=5j+11 |